Please help me with a math problem!!!!?
Submitted : 20180614 08:00:32 Popularity:
Tags: math problem
So the problem is (16^1/2)(27^1/3)
I know the answer is 4/3 but I don’t understand how to get that answer. Any help would be greatly appreciated!
16^(1/2) * 27^(1/3)
= 16^(1/2) / 27^(1/3)
= (4^2)^(1/2) / (3^3)^(1/3)
= 4^(2 * 1/2) / 3^(3 * 1/3)
= 4/3. Final.
16^(1/2)*27^(1/3) =
16^(1/2)*1/27(1/3) =
√16/³√27 = 4/3
Presuming you mean:
16^(1/2) * 27^(1/3)
There are two ways to look at this. See the 1/2 power and 1/3 power and know they are square root and cube root, or see the 2 and 3 and find expressions for the base to be a 2 and 3.
Let's do the latter.
16 = 4²
27 = 3³
So if we substitute those, we get:
(4²)^(1/2) * (3³)^(1/3)
You should have learned that if you have an exponent of an exponent it's the same as the product of the exponents on the same base. So we can change these to:
4^(2 * 1/2) * 3^(3 * (1/3))
Simplifying the products, we get:
4^(1) * 3^(1)
anything to the 1st power is just the base, and the negative exponent is the same as the reciprocal, so that gives you:
4/3
the answer is 4/3
(16^1/2)(27^1/3)
x^(a*b) = (x^a)^b
16 = 4^2
16^(1/2) = (4^2)^(1/2) = 4^1 = 4
or √16 = 4
x^(a) = 1/x^a
27 = 3^3
27^(1/3) = (3^3)^(1/3) = 3^(1) = 1/3
or 1/∛27 = 1/3
Thus 4/3 is the answer.
(16^1/2) (27^1/3)
Simply follow the proper order of operations.
(16^1/2) > when raised to the 1/2 power, this is the square root of the number, hence 4
(27^1/3) > do this on your calculator. Or, 27^1/3 would be the cube root of 27, so 3. The presence of the minus sign inverts that3, so 1/3
We now have this:
(4) (1/3) = 4/3
Do you know how to figure 16^1/2 ? And 27^1/3?


Article Source:
www.Aphotolog.Com
Answer Questions